A metal cube of length 10.0 mm at 0 ∘ C is heated to 20 0 ∘ C . Its linear expansion coefficient is 2 × 1 0 − 5 K − 1 . The percent change of its volume is:

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A metal cube of length 10.0 mm at $0^{\circ} C$ is heated to $20 0^{\circ} C$ . Its linear expansion coefficient is 2 × $1 0^{- 5} K^{- 1}$ . The percent change of its volume is:

Options:

Answer:

Solution:

$\frac{100Δ V}{V} ≃ 100 (3 α Δ T) = 100 (3) (2 \times 1 0^{- 5}) (200) = 1.2%$ . Exact geometry gives $100 [(1.004)^{3} - 1] =$ 1.2048064\%, consistent with the option precision.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

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