For three low density gases A , B , C pressure versus temperature graphs are plotted while keeping them at constant volume, as shown in the figure The temperature corresponding to the point ' K ' is:

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TestHub · Accepted Answer

In case of constant volume process, i.e., isochoric process,

From ideal gas equation,

$\frac{P}{T} = n \frac{R}{V} =$ constant

Or we have, $P = \frac{n R}{V} (t + 273)$

If $P = 0 \Rightarrow t = - 273 ° C$

Thus, when temperature goes to $- 273 ° C$ , all constituent particles get freezed and pressure goes to zero irrespective of the density of gas.

Hence, the temperature corresponding to the point $K = - 273 ° C$ .

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