Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKTGMedium2 minPYQ_2023

PhysicsMediumsingle choice

The mean free path of molecules of a certain gas at STP is $1500 d$ , where $d$ is the diameter of the gas molecules. While maintaining the standard pressure, the mean free path of the molecules at $373 K$ is approximately:

Options:

Answer:

Solution:

The mean free path is given by the relation,
$λ = \frac{R T}{\sqrt{2} π d^{2} N_{A} P}$
So, $λ \propto T$
Let $λ'$ be the new mean free path.
Hence,
$\frac{1500 d}{λ'} = \frac{273}{373}$
$\Rightarrow λ^{'} = 2049.45 d \approx 2049 d$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: PYQ_2023

Doubts & Discussion

Loading discussions...