Figure shows a cyclic process ABCDBEA performed on an ideal gas. If $P_{A} = 2 atm ., P_{B} = 4.5 atm$ . and $P_{C} = 6 atm .; V_{E} - V_{A} = 0.05$ litre, find the work done by the gas (in J) in the complete process in nearest integer. ( 1 atm , pressure $= 1 \times 1 0^{5} pa$ )

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Area of △ A BE = 2 1 ​ ( 2.5 × 1 0 5 ) ( 0.05 × 1 0 − 3 ) = 2 125 ​ = 4 25 ​ Since, △ AEB and △ BCD are similar, therefore 2.5 1.5 ​ = 0.05 C D ​ C D = 5 3 ​ × 0.05 = 0.03 Area of △ BCD = 2 1 ​ × ( 1.5 × 1 0 5 ) ( 0.03 × 1 0 − 3 ) = 2 4.5 ​ = 4 9 ​ W N ​ = 4 25 ​ − 4 9 ​ = 4 J

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