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PhysicsHeat & ThermoDifferent processesEasy2 minPYQ_2022
PhysicsEasynumerical

The total internal energy of two mole monoatomic ideal gas at temperatureT=300 Kwill be _____J. (GivenR=8.31 J mol-1·K)

Answer:
7479.00
Solution:

The internal energy of an ideal gas is a state function and is given by, U=nCvT.

For monatomic gas, Cv=32R.

Therefore, U=2×32×8.31×300=7479 J

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Different processes
2mℹ️ Source: PYQ_2022

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