A thermodynamic system is taken from an original state $D$ to an intermediate state $E$ by the linear process shown in the figure. Its volume is then reduced to the original volume from $E$ to $F$ by an isobaric process. The total work done by the gas from $D$ to $E$ to $F$ will be

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Total work done by the gas from D to E to F = Area of ∆ D E F Work done during the process D E is W DE = 1 2 600 + 300 5 - 2 J = 1350 J Work done during the process E F is W EF = - 300 × 3 = - 900 J W DEF = W DE + W EF = 450 J

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