The width of one of the two slits in a Young's double slit experiment is three times the other slit. If the amplitude of the light coming from a slit is proportional to the slit-width, the ratio

Question

The width of one of the two slits in a Young's double slit experiment is three times the other slit. If the amplitude of the light coming from a slit is proportional to the slit-width, the ratio of minimum to maximum intensity in the interference pattern is x : 4 where x is _ _ _ _ _ _ _ .

TestHub · Accepted Answer

Given amplitude ∝ slit width Also intensity ∝ ( Amplitude ) 2 ∝ ( Slit width ) 2 I 2 ​ I 1 ​ ​ = ( 1 3 ​ ) 2 = 9 ⇒ I 1 ​ = 9 I 2 ​ I m a x ​ I m i n ​ ​ = ( I 1 ​ ​ + I 2 ​ ​ I 1 ​ ​ − I 2 ​ ​ ​ ) 2 = ( 3 + 1 3 − 1 ​ ) 2 = 4 1 ​ = 4 x ​ ⇒ x = 1

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