Calculate the value of the mean free path λ for oxygen molecules at temperature 27 ° C and pressure 1 . 01 × 10 5 Pa . Assume the molecular diameter 0 . 3 nm and the gas is ideal. k = 1 . 38 × 10 - 23 J K - 1

λ = R T 2 π d 2 N A P λ = 8 . 314 × 300 2 × 3 . 14 × 0 . 3 × 10 - 9 2 × 6 . 023 × 10 23 × 1 . 01 × 10 5 λ = 102 nm

Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKTGEasy2 minPYQ_2021

PhysicsEasysingle choice

Calculate the value of the mean free path $(λ)$ for oxygen molecules at temperature $27 ° C$ and pressure $1.01 \times 10^{5} Pa$ . Assume the molecular diameter $0.3 nm$ and the gas is ideal. $(k = 1.38 \times 10^{- 23} J K^{- 1})$

Options:

Answer:

Solution:

$λ = \frac{R T}{\sqrt{2} π d^{2} N_{A} P}$

$λ = \frac{8.314 \times 300}{\sqrt{2} \times 3.14 \times {(0.3 \times 10^{- 9})}^{2} \times 6.023 \times 10^{23} \times 1.01 \times 10^{5}}$

$λ = 102 nm$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: PYQ_2021

Doubts & Discussion

Loading discussions...