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PhysicsHeat & ThermoDifferent processesEasy2 minPYQ_2020
PhysicsEasysingle choice

Match the thermodynamics processes taking place in a system with the correct conditions. In the table : Q is the heat supplied, W is the work done and U is change in internal energy of the system.

 Process Condition
(I)Adiabatic(A)W=0
(II)Isothermal(B)Q=0
(III)Isochoric(C)U0,W0,Q0
(IV) Isobaric (D)U=0

Options:

Answer:
D
Solution:

In Adiabatic ΔQ=0,i.e., Exchange of heat does not take place.

In Isothermal ΔU=0,i.e., Temperature does not change therefore internal energy also remains constant.

In Isochoric ΔW=0,i.e., Volume remains constant therefore work done is zero.

In Isobaric U0, W0, Q0
W=P.V, Volume changes so work done is not equal to zero.
U=f2PV, Volume changes therefore internal energy changes.
 Q=nCpT, Temperature changes therefore heat also changes.

 

 

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Different processes
2mℹ️ Source: PYQ_2020

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