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PhysicsHeat & ThermoFirst lawMedium2 minPYQ_2019
PhysicsMediumsingle choice

The specific heats,CpandCvof a gas of diatomic molecules,A,are given (in units ofJ mol-1 K-1) by29and22,respectively. Another gas of diatomic molecules,B,has the corresponding values30and21.If they are treated as ideal gases, then:

Options:

Answer:
B
Solution:

For A :
R=Cp-Cv=29-22=7
Cv=fR2
22=f×72
f=447=6.3
f6

(5 rotational + translational, 1 vibrational)


For B :
R=Cp-CV=30-21=9
Cv=fR2=21
f=21×29=429=4.665
f5

 (5 rotational + transitional, 0 vibrational)

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:First law
2mℹ️ Source: PYQ_2019

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