One mole of an ideal gas at an initial temperature of T K does 6 R joules of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 5/3 , the fin

Question

One mole of an ideal gas at an initial temperature of T K does 6 R joules of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 5/3 , the final temperature of gas will be:NEET 2004

TestHub · Accepted Answer

We know that work done in adiabatic process is: ​ W = V − 1 − 1 ​ ( P f ​ V f ​ − P i ​ V i ​ ) ⇒ 6 R = 3 5 ​ − 1 − 1 ​ ( T f ​ − T i ​ ) Since P V = RT } ⇒ T f ​ − T i ​ = − 4 ⇒ T f ​ = ( T − 4 ) K ​

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