For the given cyclic process C A B as shown for a gas, the work done is:

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TestHub · Accepted Answer

The work done in a cyclic process is equal to the area of closed P-V curve cycle.

Work done, $W =$ Area of $∆ C A B$

$\Rightarrow W = \frac{1}{2} \times A B \times A C$ $= \frac{1}{2} \times (6 - 1) \times (5 - 1) = 10 J$

In the given P-V graph, the process is clockwise. So, the work done will be positive which means that the system is doing the work.

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