Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKTGEasy2 minQB

PhysicsEasysingle choice

If the root mean square velocity of hydrogen molecule at a given temperature and pressure is $2 km s^{- 1},$ the root mean square velocity of oxygen at the same condition in $km s^{- 1}$ is:

Options:

Answer:

Solution:

Root mean square velocity is given by, $V_{r m s} = \sqrt{\frac{3 R T}{M}}$

Therefore, $\frac{V_{1}}{V_{2}} = \sqrt{\frac{M_{2}}{M_{1}}} \Rightarrow \frac{2}{V_{2}} = \sqrt{\frac{32}{2}}$

$\Rightarrow V_{2} = 0.5 km s^{- 1}$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: QB

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