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PhysicsHeat & ThermoDifferent processesMedium2 minPYQ_2014
PhysicsMediumsingle choice

The equation of state for a gas is given by PV = nRT + α V , where n is the number of moles and α is a positive constant. The initial temperature and pressure of one mole of the gas contained in a cylinder are T0and P0respectively. The work done by the gas when its temperature doubles isobarically will be :

Options:

Answer:
C
Solution:

PV = nRT + α V

P 0 dV dT = R + α dV dT

P 0 - α dV dT = R

∴    dV = RdT P 0 - α

∴    W = P 0 dV = T 0 2 T 0 P 0 R P 0 - α dT

= P 0 T 0 R P 0 - α

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Different processes
2mℹ️ Source: PYQ_2014

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