Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKTGEasy2 minPYQ_2021

PhysicsEasysingle choice

The volume $V$ of an enclosure contains a mixture of three gases, $16 g$ of oxygen, $28 g$ of nitrogen and $44 g$ of carbon dioxide at absolute temperature $T$ . Consider $R$ as universal gas constant. The pressure of the mixture of gases is :

Options:

Answer:

Solution:

$P V = (n_{1} + n_{2} + n_{3}) R T$

$P \times V = [\frac{16}{32} + \frac{28}{28} + \frac{44}{44}] R T$

$P V = [\frac{1}{2} + 1 + 1] R T$

$P = \frac{5}{2} \frac{R T}{V}$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: PYQ_2021

Doubts & Discussion

Loading discussions...