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PhysicsHeat & ThermoCalorimetryMedium2 minPYQ_2014
PhysicsMediumsingle choice

Water of volume 2 L in a closed container is heated with a coil of 1 kW. While water is heated, the container loses energy at a rate of 160 J/s. In how much time will the temperature of water rise from 27oC to 77oC ? (Specific heat of water is 4.2 kJ/kg and that of the container is negligible).

Options:

Answer:
A
Solution:

P = 1 0 0 0  watt

∴   Pin=1000-160 J/s=840 J/s

Now, d Q dt = ms dT dt

∴    840=msdTdt

∴    dt = ms 8 4 0 dT

Integrating both sides we have;

t = ms 8 4 0 dT

= 2 × 1 0 0 0 × 1 0 - 6 × 1 0 0 0 × 4.2 × 1 0 0 0 8 4 0 × 5 0

= 5 0 0 sec

= min 2 0 sec

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Calorimetry
2mℹ️ Source: PYQ_2014

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