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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoSecond Law of ThermodynamicsMedium2 minPYQ_2002

PhysicsMediumsingle choice

The efficiency of the Carnot engine is $50%$ and the temperature of the sink is $500 K$ . If the temperature of the source is kept constant and its efficiency raised to $60%$ , then the required temperature of the sink will be:NEET 2002

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Solution:

$% η = (1 - \frac{T _{2}}{T _{1}}) \times 100 ∴ For 50%, \frac{50}{100} = 1 - \frac{50}{11} \Rightarrow T_{1} = 1000 K aim for 60%, \frac{60}{100} = 1 - \frac{T _{2}}{1000} \Rightarrow T_{2} = 400 K$

Stream:NEETSubject:PhysicsTopic:Heat & ThermoSubtopic:Second Law of Thermodynamics

⏱ 2mℹ️ Source: PYQ_2002

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