Two liquid A & B of specific heat ratio 1 : 2 are at temperature 2 θ and θ respectively. If they are mixed, then choose CORRECT statement(s) : (ignore any heat loss and liquid does not change its stat

Question

Two liquid A & B of specific heat ratio 1 : 2 are at temperature 2 θ and θ respectively. If they are mixed, then choose CORRECT statement(s) : (ignore any heat loss and liquid does not change its state)

TestHub · Accepted Answer

Specific heats: s_A : s_B = 1 : 2; initial temperatures 2θ and θ.

Equal masses m mixed: $T = \frac{m s _{A} ( 2 θ ) + m s _{B} θ}{m s _{A} + m s _{B}} = \frac{2 θ + 2 θ}{1 + 2} = \frac{4 θ}{3}$

So (A) is wrong and (B) is correct.

If the temperature change is the same for both: $m_{A} s_{A} Δ T = m_{B} s_{B} Δ T \Rightarrow \frac{m _{A}}{m _{B}} = \frac{s _{B}}{s _{A}} = 2$

So (C) is correct and (D) is wrong.

Hence (B) and (C).

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