Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationEnergy & PotentialMedium2 minPYQ_2023

PhysicsMediumsingle choice

If $V$ is the gravitational potential due to sphere of uniform density on it's surface, then it's value at the center of sphere will be:

Options:

Answer:

Solution:

Potential due to sphere
$V = \frac{GM}{2 R ^{3}} (3 R^{2} - r^{2})$
At surface $r = R \Rightarrow V = (\frac{GM}{R})$
At centre, $r = 0$
$∴ V_{0} = \frac{3 GM}{2 R} = (\frac{3 V}{2})$

Stream:BITSATSubject:PhysicsTopic:GravitationSubtopic:Energy & Potential

⏱ 2mℹ️ Source: PYQ_2023

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