A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is 11 kms − 1 , the escape velocity from th

Question

A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is $11 kms^{- 1}$ , the escape velocity from the surface of the planet would be

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Answer:

C

Solution:

$v_{esc} = \frac{2 GM}{R} = \frac{2 G \times 10 M}{R /10} = 10 \times 11 = 110 km / s$

TestHub · Accepted Answer

v esc ​ = R 2 GM ​ ​ = R /10 2 G × 10 M ​ ​ = 10 × 11 = 110 km / s

Physics - Gravitation Question with Solution | TestHub

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