The depth at which acceleration due to gravity becomes 2 n g is ( R = radius of earth, g = acceleration due to gravity on earth's surface, n is integer)

The gravitational acceleration at depth is given as g d = g [ 1 − R d ] Given g d = 2 n g ∴ 2 n g R d d = g [ 1 − R d ] = 1 − 2 n 1 = [ 2 n 2 n − 1 ] R

Start Free Mock LoginAlready registered? Login here

Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationField & ForceHard2 minPYQ_2023

PhysicsHardsingle choice

The depth at which acceleration due to gravity becomes $\frac{g}{2 n}$ is $(R =$ radius of earth, $g =$ acceleration due to gravity on earth's surface, $n$ is integer)

Options:

Answer:

Solution:

The gravitational acceleration at depth is given as $g_{d} = g [1 - \frac{d}{R}]$ Given $g_{d} = \frac{g}{2 n}$ $∴ \frac{g}{2 n} \frac{d}{R} d = g [1 - \frac{d}{R}] = 1 - \frac{1}{2 n} = [\frac{2 n - 1}{2 n}] R$

Stream:MHT_CETSubject:PhysicsTopic:GravitationSubtopic:Field & Force

⏱ 2mℹ️ Source: PYQ_2023

Doubts & Discussion

Loading discussions...