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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationField & ForceEasy2 minPYQ_2012

PhysicsEasysingle choice

The height at which the weight of a body becomes $1/16$ th, its weight on the surface of earth (radius $R$ ), is

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Answer:

Solution:

According to question $\frac{GM m}{( R + h ) ^{2}} = \frac{1}{16} \frac{GM m}{R ^{2}}$ $\frac{1}{( R + h ) ^{2}} = \frac{1}{16 R ^{2}} or \frac{R}{R + h} = \frac{1}{4} or \frac{R + h}{R} = 4 h = 3 R$

Stream:NEETSubject:PhysicsTopic:GravitationSubtopic:Field & Force

⏱ 2mℹ️ Source: PYQ_2012

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