Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationSatellite MotionHard2 minPYQ_2023

PhysicsHardsingle choice

If the distance of the earth from Sun is $1.5 \times 10^{6} km$ , then the distance of an imaginary planet from Sun, if its period of revolution is $2.83$ years is:

Options:

Answer:

Solution:

From Kepler's law of periods, we know that

$T^{2} \propto R^{3} \Rightarrow {(\frac{T_{1}}{T_{2}})}^{2} = {(\frac{R_{1}}{R_{2}})}^{3}$

$\Rightarrow {(\frac{1}{2.83})}^{2} = {(\frac{1.5 \times 10^{6}}{R_{2}})}^{3}$

$\Rightarrow R_{2} = {[{(2.83)}^{2} \times {(1.5 \times 10^{6})}^{3}]}^{\frac{1}{3}}$

$= 8^{\frac{1}{3}} \times 1.5 \times 10^{6} = 3 \times 10^{6} km$

Stream:JEESubject:PhysicsTopic:GravitationSubtopic:Satellite Motion

⏱ 2mℹ️ Source: PYQ_2023

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