Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationField & ForceMedium2 minPYQ_2023

PhysicsMediumsingle choice

Two identical particles each of mass ' $m$ ' go round a circle of radius $a$ under the action of their mutual gravitational attraction. The angular speed of each particle will be:

Options:

Answer:

Solution:

Radius of circle, $r = a$
Centrifugal force, $F = m ω^{2} r$
$\Rightarrow \frac{Gmm}{( 2 a ) ^{2}} = m ω^{2} a (∵ F = \frac{GM M _{2}}{d})$
Here $M_{1} = m; M_{2} = m$ and $d = 2 a$
$\Rightarrow$ angular speed, $ω = \frac{G m}{4 a ^{3}}$

Stream:BITSATSubject:PhysicsTopic:GravitationSubtopic:Field & Force

⏱ 2mℹ️ Source: PYQ_2023

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