A geostationary satellite is orbiting around an arbitrary planet P at a height of 11 R above the surface of P , R being the radius of P . The time period of another satellite in hours at a height of 2

Question

A geostationary satellite is orbiting around an arbitrary planet $P$ at a height of $11 R$ above the surface of $P$ , $R$ being the radius of $P$ . The time period of another satellite in hours at a height of $2 R$ from the surface of $P$ is ________ has the time period of $24 hours .$

Options:

Answer:

C

Solution:

$T \propto R^{3 / 2}$

$\frac{24}{T} = {(\frac{12 R}{3 R})}^{3 / 2} \Rightarrow T = 3 hr$

TestHub · Accepted Answer

T ∝ R 3 / 2 24 T = 12 R 3 R 3 / 2 ⇒ T = 3 hr

Physics - Gravitation Question with Solution | TestHub

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