Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationKepler's LawEasy2 minPYQ_2020

PhysicsEasysingle choice

The period of revolution of planet $A$ around the sun is eight times that of $B$ . How many times is the distance of $A$ from the sun, greater than that of $B$ ?

Options:

Answer:

Solution:

As $T^{2} \propto r^{3}$ ,

so, $\frac{T_{A}^{2}}{T_{B}^{2}} = \frac{r_{A}^{3}}{r_{B}^{3}}$

or $r_{A} = 4 r_{B}$

so, $r_{A} - r_{B} = 4 r_{B} - r_{B} = 3 r_{B}$

Subject:PhysicsTopic:GravitationSubtopic:Kepler's Law

⏱ 2mℹ️ Source: PYQ_2020

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