Physics - Gravitation Question with Solution | TestHub

We know that, on going below the earth surface,$g$decreases, which is given by

$g^{\prime }=g\left(1-\frac{d}{R_e}\right)$.....(i)

where,$d=$depth

$R_e=$Radius of earth.

At the centre of earth,$d=R_e$[$\therefore$from Equation (i)]

$g^{\prime }=g\left(1-\frac{R_e}{R_e}\right)$

$g^{\prime }=0$

Hence, weight of the body at the centre,

$w=m{g}^{\prime }$

$=m\times 0$

$=0$