Physics - Gravitation Question with Solution | TestHub

Using Kepler's III^rdlaw of planetary motion,

$\mathrm{T}=2\mathrm{\pi }\sqrt{\frac{{\mathrm{r}}^3}{\mathrm{GM}}}$or${\mathrm{T}}^2\propto {\mathrm{r}}^3$

Frequency,$\mathrm{f}=\frac{1}{\mathrm{T}}=\frac{1}{2\mathrm{\pi }}\sqrt{\frac{\mathrm{GM}}{{\mathrm{r}}^3}}$

Frequency is independent of the mass of the satellite.

Hence, required ratio$=1:1$