When the value of acceleration due to gravity ' g ' becomes ( 3 g ) above the earth's surface at height 'h' then relation between 'h' and 'R' is [R = radius of the earth]

3 g = ( R + h ) 2 GM g = R 2 GM ∴ 3 g ( R + h ) 2 = g R 2 ( R + h ) 2 = 3 R 2 R + h = 3 R ∴ h = 3 R − R = ( 3 − 1 ) R

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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationField & ForceMedium2 minPYQ_2020

PhysicsMediumsingle choice

When the value of acceleration due to gravity ' $g$ ' becomes $(\frac{g}{3})$ above the earth's surface at height 'h' then relation between 'h' and 'R' is [R = radius of the earth]

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Solution:

$\frac{g}{3} = \frac{GM}{( R + h ) ^{2}} g = \frac{GM}{R ^{2}}$ $∴ \frac{g}{3} (R + h)^{2} = g R^{2}$ $(R + h)^{2} = 3 R^{2}$ $R + h = 3 R ∴ h = 3 R - R = (3 - 1) R$

Stream:MHT_CETSubject:PhysicsTopic:GravitationSubtopic:Field & Force

⏱ 2mℹ️ Source: PYQ_2020

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