A simple pendulum doing small oscillations at a place R height above earth surface has time period of T 1 = 4 s . T 2 would be it's time period if it is brought to a point which is at a heigh

Question

A simple pendulum doing small oscillations at a place $R$ height above earth surface has time period of $T_{1} = 4 s$ . $T_{2}$ would be it's time period if it is brought to a point which is at a height $2 R$ from earth surface. Choose the correct relation $[R =$ radius of earth $]$ :

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Answer:

D

Solution:

$T_{1} = 2 π \frac{ℓ}{GM} (2 R)^{2} T_{2} = 2 π \frac{ℓ}{GM} (3 R)^{2} ∴ \frac{T _{1}}{T _{2}} = \frac{2}{3}$

TestHub · Accepted Answer

​ T 1 ​ = 2 π GM ℓ ​ ( 2 R ) 2 ​ T 2 ​ = 2 π GM ℓ ​ ( 3 R ) 2 ​ ∴ T 2 ​ T 1 ​ ​ = 3 2 ​ ​

Physics - Gravitation Question with Solution | TestHub

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