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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationField & ForceEasy2 minPYQ_2020

PhysicsEasysingle choice

If a man weighs $90 kg$ on the surface of the earth, the height above the surface of the earth of radius $R,$ where the weight is $30 kg$ is

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Answer:

Solution:

Given, $\frac{m g'}{m g} = \frac{30}{90}$ or $\frac{g'}{g} = \frac{1}{3}$

Now, $g^{'} = g \frac{R^{2}}{{(R + h)}^{2}}$ or $\frac{g'}{g} = \frac{R^{2}}{{(R + h)}^{2}} = \frac{1}{3}$

or $\frac{R}{R + h} = \frac{1}{\sqrt{3}}$ or $(R + h) = \sqrt{3} R$

or $h = (\sqrt{3} - 1) R = 0.73 R$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:GravitationSubtopic:Field & Force

⏱ 2mℹ️ Source: PYQ_2020

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