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PhysicsGravitationKepler's LawMedium2 minQB

PhysicsMediuminteger

The period of revolution of planet in terms of orbital radius d, Mass of sun m is $T = \frac{2 π d ^{x /2}}{yGm}$ . Then $x + y$ is :-

Answer:

Solution:

T = 2.pi.sqrt(d^3/(Gm)) = 2.pi.d^(3/2)/sqrt(Gm). Comparing with T = 2.pi.d^(x/2)/sqrt(yGm): x = 3 and y = 1, so x + y = 4.

Stream:JEESubject:PhysicsTopic:GravitationSubtopic:Kepler's Law

⏱ 2mℹ️ Source: QB

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