Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationField & ForceEasy2 minPYQ_2020

PhysicsEasysingle choice

$A, B, C$ and $D$ are four particles with each of mass $M$ lying on the vertices of a square of side $a$ . They always move along a common circle with velocity $v$ under mutual gravitational force. Find $v$ so that they always remain on the vertices of the square

Options:

Answer:

Solution:

From the above figure, it is clear that

$F_{n e t} = \sqrt{2} F_{1} + F_{3} = \frac{M V^{2}}{R}$ $(F_{1} = F_{2})$

$\sqrt{2} \frac{G M^{2}}{a^{2}} + \frac{G M^{2}}{{(a \sqrt{2})}^{2}} = \frac{M v^{2}}{a / \sqrt{2}}$

$v = \sqrt{\frac{G M (1 + 2 \sqrt{2})}{2 \sqrt{2} a}}$

Subject:PhysicsTopic:GravitationSubtopic:Field & Force

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...