The given figure shows the elliptical orbit of a planet $m$ about the sun $S$ . If $t_{1}$ is the time taken by the planet to move from $C$ to $D$ and $t_{2}$ is the time taken by the planet to move from $A$ to $B$ , then the relation between $t_{1}$ and $t_{2}$ is [Given, $a r e a S C D = 2 (a r e a S A B)$ ]

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According to kepler's second law
Equal areas are swept in equal time. t₁, the time taken to go from C to D = 2t₂where t₂is the time taken to go from A to B. As it is given that area SCD = 2SAB.

Physics - Gravitation Question with Solution | TestHub

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