Physics - Gravitation Question with Solution | TestHub

Kinetic energy, $K=\frac{1}{2}m{v}_0^2$ or $v_0=\sqrt{\frac{2K}{m}}$ When kinetic energy is doubled, then $v_0^{\prime }=\sqrt{\frac{2\times 2K}{m}}=\sqrt{2}\sqrt{\frac{2K}{m}}=\sqrt{2}{v}_0$ But $\sqrt{2}{v}_0=v_e$ (escape velocity) Hence satellite will escape out of earth's gravitational field.