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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationEnergy & PotentialEasy2 minPYQ_2020

PhysicsEasysingle choice

A body is projected up with a velocity equal to $\sqrt{\frac{9 G M}{8 R}}$ , where $M$ is the mass of the earth and $R$ is the radius of the earth. The maximum distance it reaches from the centre of the earth is

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Answer:

Solution:

Let us assume that the maximum distance of the body from the centre of the earth is $h$ .

Applying the conservation of mechanical energy, we get

$\frac{1}{2} m {(\sqrt{\frac{9 G M}{8 R}})}^{2} - \frac{G M m}{R} = - \frac{G M m}{h}$

$- \frac{7}{16} \frac{G M m}{R} = - \frac{G M m}{h}$

$\Rightarrow h = \frac{16 R}{7}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:GravitationSubtopic:Energy & Potential

⏱ 2mℹ️ Source: PYQ_2020

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