Physics - Gravitation Question with Solution | TestHub

We know that The potential energy of the satellite $$U=-\frac{G{M}_{e}m}{R_0}$$ The kinetic energy of the satellite $$K=\frac{1}{2}\frac{G{M}_{e}m}{R_e}$$ The total energy $$\begin{array}{rl}E=U+K& =-\frac{G{M}_{e}m}{R}+\frac{1}{2}\frac{G{M}_{e}m}{R_0}\\ E& =-\frac{1}{2}\frac{G{M}_{e}m}{R}\\ 2E& =-\frac{G{M}_{e}m}{R_0}\Rightarrow -2E=U\end{array}$$ So. $\mathrm{PE}=-2(\mathrm{TE})$ $$\mathrm{PE}=-2E$$