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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationEnergy & PotentialMedium2 minQB

PhysicsMediumsingle choice

A mass m , travelling at speed $V_{0}$ in a straight line from far away is deflected when it passes near a black hole of mass M which is at a perpendicular distance R from the original line of flight. The distance of closest approach 'a' between the mass and the black hole is given by the relation :

Options:

Answer:

Solution:

$mv_{0} R = mva$

$\frac{1}{2} m v_{0}^{2} = \frac{1}{2} m v^{2} - \frac{GM m}{a}$

Eliminating v between the two equations gives a quadratic in a whose positive root gives the distance of closest approach - option (D).

Stream:JEESubject:PhysicsTopic:GravitationSubtopic:Energy & Potential

⏱ 2mℹ️ Source: QB

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