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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationEnergy & PotentialMedium2 minPYQ_2013

PhysicsMediumsingle choice

Two particles of equal mass $m$ go round a circle of radius $R$ under the action of their mutual gravitational attraction. The speed of each particle is

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Solution:

From given condition $\frac{Gmm}{( 2 R ) ^{2}} = \frac{mv ^{2}}{R}, v = \frac{Gm}{4 R} = \frac{1}{2} \frac{Gm}{R}$

Stream:VITEEESubject:PhysicsTopic:GravitationSubtopic:Energy & Potential

⏱ 2mℹ️ Source: PYQ_2013

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