Physics - Gravitation Question with Solution | TestHub

Earth rotates about its own axis in 24 h . So, $T=24\times 60\times 60\mathrm{s}$ So, angular speed of earth about its own axis $\omega =\frac{2\pi }{T}=\frac{2\pi }{24\times 60\times 60}\mathrm{rad}/\mathrm{s}$ At equator, $g^{\prime }=g-R_e{\omega }^{\prime 2}$ or $0=g-R_e{\omega }^{\prime 2}$ or ${\omega }^{\prime }=\sqrt{\frac{g}{R_e}}=\frac{2\pi }{84.6\times 60}$ $\therefore \frac{{\omega }^{\prime }}{\omega }=\frac{24\times 60\times 60}{84.6\times 60}\approx 17$ $\Rightarrow {\omega }^{\prime }=17\omega$ So, value of $x$ is 17 .