Physics - Gravitation Question with Solution | TestHub

The centripetal force required for a car (mass $m$ ) to take a sharp turn of radius $r$ with velocity $v$ is $$F=\frac{m{v}^2}{r}$$ Given, $m=500\mathrm{kg}$, $$\begin{array}{l}v=36\mathrm{km}/\mathrm{h}=36\times \frac{5}{18}=10\mathrm{m}/\mathrm{s},r=50\mathrm{m}\\ \text{ Hence, }F=\frac{500\times (10{)}^2}{50}=1000\mathrm{N}\end{array}$$