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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationSatellite MotionMedium2 minPYQ_2005

PhysicsMediumsingle choice

For a satellite in an orbit around the earth, the ratio of kinetic energy to potential energy is:

Options:

Answer:

Solution:

$- \frac{GMm}{R ^{2}} + m ω^{2} R = 0$ $∴ \frac{GMm}{R ^{2}} K.E. = \frac{1}{2} I ω^{2} = m ω^{2} R = \frac{1}{2} m R^{2} ω^{2} = \frac{GMm}{2 R}$ $P . E . = - \frac{GMm}{R} ∴ K . E = \frac{∣ P \cdot E ∣}{2} ∴ \frac{K \cdot E}{P \cdot E} = \frac{1}{2}$

Stream:NEETSubject:PhysicsTopic:GravitationSubtopic:Satellite Motion

⏱ 2mℹ️ Source: PYQ_2005

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