Two stars of mass m and 3m separated by distance r are moving in circular path about their centre of mass due to mutual gravitation force. The angular velocity of any star will be

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TestHub · Accepted Answer

The lighter star is three-quarters of the separation from the centre of mass.

$\frac{3 G m ^{2}}{r ^{2}} = m \frac{3 r}{4} ω^{2}$

$ω^{2} = \frac{4 G m}{r ^{3}}$

$ω = \frac{4 G m}{r ^{3}}$

Both stars share this angular speed. Answer C.

Physics - Gravitation Question with Solution | TestHub

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JEE Main 2027 (Class 12+)