Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsTIR/Prism and DispersionMedium2 minQB

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The refracting angle of a prism is $A$ and the refractive index of the material of the prism is $cot (A /2)$ . The angle of minimum deviation is :

Answer:

Solution:

$μ = \frac{sin \frac{A + δ _{m}}{2}}{sin \frac{A}{2}} = cot \frac{A}{2}$

$sin \frac{A + δ _{m}}{2} = cos \frac{A}{2}$

$\frac{A + δ _{m}}{2} = 9 0^{\circ} - \frac{A}{2}$

$δ_{m} = 18 0^{\circ} - 2 A$

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:TIR/Prism and Dispersion

⏱ 2mℹ️ Source: QB

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