An equilateral prism deviates a ray through 4 0 ∘ for two angles of incidences differing by 2 0 ∘ . The possible angles of incidences are :

i 1 + i 2 = δ + A = 4 0 ∘ + 6 0 ∘ = 10 0 ∘ i 1 − i 2 = 2 0 ∘ i 1 = 6 0 ∘ , i 2 = 4 0 ∘

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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsTIR/Prism and DispersionMedium2 minQB

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An equilateral prism deviates a ray through $4 0^{\circ}$ for two angles of incidences differing by $2 0^{\circ}$ . The possible angles of incidences are :

Options:

Answer:

Solution:

$i_{1} + i_{2} = δ + A = 4 0^{\circ} + 6 0^{\circ} = 10 0^{\circ}$

$i_{1} - i_{2} = 2 0^{\circ}$

$i_{1} = 6 0^{\circ}, i_{2} = 4 0^{\circ}$

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:TIR/Prism and Dispersion

⏱ 2mℹ️ Source: QB

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