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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsOptical instrumentsMedium2 minQB

PhysicsMediumsingle choice

In compound microscope the focal length of objective lens is 1.2 cm and focal length of eye piece is 3.0 cm. When object is kept at 1.25 cm in front of objective, final image is formed at infinity. Magnifying power of the compound microscope should be:

Options:

Answer:

Solution:

$1/ v_{o} = 1/ f_{o} - 1/ u_{o} = 1/1.2 - 1/1.25 \Rightarrow v_{o} = 30 cm; m_{o} = 30/1.25 = 24$ . Final image at infinity: $m_{e} = D / f_{e} = 25/3$ . $m = 24 \times 25/3 = 200$ .

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Optical instruments

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