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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensMedium2 minQB

PhysicsMediumsingle choice

A concave lens with unequal radii of curvature made of glass ( $μ_{g} = 1.5$ ) has a focal length of 40 cm in air. If it is immersed in a liquid of refractive index $μ_{l} = 2$ , then

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Solution:

$\frac{1}{f} = (μ_{g} - 1) (\frac{1}{R _{1}} - \frac{1}{R _{2}})$ . In the liquid: $f_{l} = f \frac{μ _{g} - 1}{μ _{g} / μ _{l} - 1} = - 40 \times \frac{0.5}{0.75 - 1} = + 80$ cm (convex nature).

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: QB

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