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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsReflection at curved surfaceMedium2 minQB

PhysicsMediuminteger

Radius of curvature of mirror is $3 m$ then find distance of point on principle axis from centre of curvature where light ray appears to cut it after reflection from mirror.

Answer:

Solution:

The ray strikes the mirror at a height R/2, so $sin θ = \frac{R /2}{R} = \frac{1}{2} \Rightarrow θ = 3 0^{\circ}$

The reflected ray cuts the principal axis at a distance from the centre of curvature $d = \frac{R /2}{c o s θ} = \frac{3 /2}{3 /2} = 1 m$

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Reflection at curved surface

⏱ 2mℹ️ Source: QB

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