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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensMedium2 minQB

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A graph is drawn with $\frac{1}{u}$ along the $x$ -axis and $\frac{1}{v}$ along the $y$ -axis for a convex lens (magnitudes). If the intercept on the $y$ -axis is $0.25 m^{- 1}$ , the focal length of the lens is (in meter)

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Answer:

Solution:

$\frac{1}{v} = - \frac{1}{u} + \frac{1}{f}$

At the $y$ -intercept $\frac{1}{u} = 0$ , so $\frac{1}{v} = \frac{1}{f}$

$f = \frac{1}{0.25} = 4$ m

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: QB

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