Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensMedium2 minQB

PhysicsMediumsingle choice

. An object is placed 15 cm in front of a diverging lens whose focal length is 12 cm. Where will the image be located (in cm)?

Answer:

Solution:

$\frac{1}{v} = \frac{1}{f} + \frac{1}{u} = - \frac{1}{12} - \frac{1}{15} = - \frac{9}{60} \Rightarrow v = - 6.7 cm$

The image is 6.7 cm from the lens on the object side (virtual). Hence (A).

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: QB

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